Question

Please Answer the above question
I will mark you as Brainliest
Chapter - Linear equation in one variable​

Answer 1

Step-by-step explanation:

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3(y−5)−16y=12−2(y−3)

3y−15−16y=12−2y+6

3y−16y+2y=12+6+15

−11y=33

∴y=−3

Answer 2

Let's solve your equation step-by-step.

$\dfrac{(y-5)}{7} - \dfrac{(y+3)}{5} = 2$

Step 1: Simplify the equation

⇒ $\dfrac{(y-5)}{7} - \dfrac{(y+3)}{5} = 2$

⇒ $\dfrac{y-5}{7} - \dfrac{y+3}{5} = 2$

⇒ $\dfrac{y}{7} - \dfrac{5}{7} - \dfrac{y}{5} - \dfrac{3}{5} = 2$

Step 2: Combine Like Terms

⇒ $\dfrac{y}{7} - \dfrac{y}{5} - \dfrac{5}{7} - \dfrac{3}{5}) = 2$

⇒ $\dfrac{y\times 5 }{7\times 5 } - \dfrac{y\times 7 }{5\times 7 } - \dfrac{5\times 5 }{7\times 5 } - \dfrac{3\times 7 }{5\times 7 } = 2$

⇒ $\dfrac{5y }{35 } - \dfrac{7y }{35 } - \dfrac{25 }{35 } - \dfrac{21 }{35 } = 2$

⇒ $\dfrac{-2y }{35 } - \dfrac{46 }{35 } = 2$

Step 3: Add $\frac{46}{35}$ to both sides of the equation.

⇒ $\dfrac{-2y }{35 } - \dfrac{46 }{35 } + \dfrac{46}{35} = 2 + \dfrac{46}{35}$

⇒ $\dfrac{-2y }{35 } = \dfrac{70}{35} + \dfrac{46}{35}$

⇒ $\dfrac{-2y }{35 } = \dfrac{116}{35}$

Step 4: Multiply $\frac{35}{-2}$ to both sides of the equation.

⇒ $\dfrac{35}{-2} \times \dfrac{-2y }{35 } = \dfrac{35}{-2} \times \dfrac{116}{35}$

⇒ $y = \dfrac{116}{-2}$

⇒ $y = -58$

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Let's verify if y = -58

⇒ $\dfrac{(y-5)}{7} - \dfrac{(y+3)}{5} = 2$

⇒ $\dfrac{(-58-5)}{7} - \dfrac{(-58+3)}{5} = 2$

⇒ $\dfrac{(-63)}{7} - \dfrac{(-55)}{5} = 2$

⇒ $-9 -(-11) = 2$

⇒ $-9+11=2$

⇒ $2=2$

∴ y = -58 in the given equation.

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