Question

Please answer the above question with explaination

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Answer 1

Answer:

Option C

$3.0115 \times 10 {}^{24}$

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Answer 2

Answer:

c) 3.0115 × 10²⁴ protons

Explanation:

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Given :-

Amount of Calcium Carbonate (CaCO₃) = 10 grams

Avogadro's Number , Nₐ = 6.023 × 10²³

To Find :-

Number of protons in 10g of CaCO₃ = ??

Solution :-

We know that,

Molar Mass of CaCO₃ = 40 + 12 + (3×16) = 52+48 = 100

No. of moles = Given Mass / Molar Mass

           = 10/100

           = 1/10

           = 0.1 mole

Also,

No. of moles = No. of Molecules / 6.023 × 10²³

So,

No. of Molecules = No. of moles × 6.023 × 10²³

                              = 0.1 × 6.023 × 10²³

                              = 6.023 × 10²² molecules

Total no. of protons in CaCO₃

= No. of Protons in Ca + No. of protons in C + 3 × No. of protons in O

= 20 + 6 + 3×8

= 20 + 6 + 24

= 20 + 30

= 50

Hence,

Total no. of Protons in CaCO₃ = 50 × 6.022 × 10²²

                                                   = 3.0115 × 10²⁴ Protons

Answer :-

Total number of protons in 10g of Calcium Carbonate is 3.0115 × 10²⁴ protons.

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