Question

Please answer the attach questions.

Answer 1

Given:-

$volume = 48 \: {m}^{3}$

and we know,

$volume = base \: area\times length$

so,

$48 = base \: area \: \times 6$

$base \: area \: = 8 \: {m}^{2}$

so,

area of one face circular region=8 m^2

area of both circular faces = 8*2= 16 m^2

and we knoe,

$base \: area = \pi {r}^{2}$

$8 = \frac{22}{7} \times {r}^{2}$

$r = \sqrt{ \frac{8 \times 7}{22} }$

$r = 0.34 \: m\: (approx)$

so,

length of radius=0.34 m (approx)

Answer 2

Answer:

$h = 6m \\ v = 48 {m}^{3} \\ a). \: area \: of \: circular \: face \: = \frac{v}{h } \\ = \frac{48}{6} \\ = 8 {m}^{2} \\ b) area \: of \: circular \: face \: = 8 {m}^{2} \: \\2\pi \times {r}^{2} = 8 \\ \frac{22}{7 \ } \times {r}^{2} = \frac{8}{2} \\ {r}^{2} = {4} \times \frac{7}{22} \\ {r}^{2} = \frac{14}{11} \\ r = \sqrt{ \frac{14}{11} }$