Question

please answer the attached question​

Answer 1

Explanation:

Refer to the attachment.

1)

When 4-hydroxyethyl phenol reacts with HBr then, it forms 4-bromoethyl phenol.

2)

When cyclohexanol reacts in the presence of red phosphorus with I2 it forms 1-iodo cyclohexane.

Additional information :-

• Bromoalkanes and iodoalkane are prepared by the reaction of PBr3 and PI3, respectively with the alcohols.
• PBr3 and PI3 are usually generated in situ by the reaction of red phosphorus with bromine and iodine respectively.