Question

please answer the attached question














answer and win points

Answer 1

Extend the line segment AE to the line segment DC.

Now in triangle AEC
angle EAC+angleE+angle C = 180°
angle EAC=180-angle E-angle C
180-angle DAE = 180-angle E- angle C
angle DAE = angle E - angle C
angle DAE+angle C=angle E

Hence prooved.

Answer 2

Hey mate!

Here's your answer!!

(Take Δ as angle)

By angle sum property, we have,

ΔBAE = ΔAEF + ΔFAE....(1)

Since, AB and CD are parallel and EC is transversal, the corresponding angles are equal.

Hence, ΔAFE = ΔDCE...(2)
Thus, from (1) and (2), we have,

ΔBAE - ΔAEF = ΔDCE
ΔBAE - ΔDCE = ΔAEF
ΔBAE - ΔDCE = ΔAEC

Hence proved.

$hope \: it \: helps \: you.$
#BE BRAINLY

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