Please answer the below question
Qns 20
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3
Answer:
Step-by-step explanation:
a+b=100°( exterior angle of triangle) ---(1)
In triangle DEB,
a+40°+90°=180°( angle sum property in triangle)
=> a= 50°
Putting in (1)
b=a=50°
Answered by
2
Answer: a = 50 degree
b = 50 degree
Step-by-step explanation:
<DFC = 180 - 100 = 80 degree [Angle property of straight line]
<AFE = 80 degree [vertical opposite angle to <DFC]
<AEF = 90 [perpendicular line]
In Δ AEF
<EAF = 180 -(90+80) = 180 - 170 = 10 degree
In Δ ACB
<ACB = 180 - (10+40) = 180-50 = 130 degree
In the straight line DCB, <C = 180 degree
Hence b = 180 - 130 = 50 degree
In Δ DFC
< FDC = 180 - (80+b) = 180 - (80+50) = 50 degree.
a = 50 degree
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