Question

please answer the both question it's urgent​

Answer 1

Step-by-step explanation:

Given that

AB is parallel to DE

angle BAC=35

angleCDE=53

To find angle DCE

proof-

angleBAC=angleCED(alernate interor anglr)

angleCBD =35

so by angle sum proparty you can find angleDCE

answer is (b) 92

second question answer is

option (a)18

Answer 2

For Fig:. 6.207

Given :

• Three angles are 2x , 3x and 5x.

To Find :

• Value of x

Solution :

As we know that the sum of angles which are made on one line is 180°.So,

$\longmapsto\tt{2x+3x+5x=180\degree(Angles\:on\:one\:line)}$

$\longmapsto\tt{10x=180\degree}$

$\longmapsto\tt{x=\cancel\dfrac{180}{10}}$

$\longmapsto\tt\bold{x=18\degree}$

Value of x is 18°.

Option a)18° is Correct...

_______________________

For Fig:. 6.208

Given :

• ∠BAC = 35°
• ∠CDE = 53°

To Find :

• ∠DCE

Solution :

$\longmapsto\tt{\angle{BAC}=\angle{CED}(Alternate\:Angles)}$

$\longmapsto\tt{\angle{CDE}=35\degree}$

In Δ CDE :

$\longmapsto\tt{\angle{CDE}+\angle{CED}+\angle{DCE}=180\degree(A.S.P)}$

$\longmapsto\tt{53\degree+35\degree+\angle{DCE}=180\degree}$

$\longmapsto\tt{\angle{DCE}=180\degree-88\degree}$

$\longmapsto\tt\bold{\angle{DCE}=92\degree}$

Option b)92° is Correct.