please answer the both the above question fast
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2)2 9.2
3) 3)1.33
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3) 3)1.33
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sonu806:
but explain
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1)
Kinetic engergy of hammer will get converted in heat energy of nail
1/2 Mv²/ 4.2= msΔT
divided by 4.2 to make it into calory
ΔT= 1/2 Mv² /4.2 ms
.....where M is mass of hammer and m is mass of nail.
2)
power =workdone /time
power = mL/t
where m is mass of ice , l is latent heat. and t is time
Kinetic engergy of hammer will get converted in heat energy of nail
1/2 Mv²/ 4.2= msΔT
divided by 4.2 to make it into calory
ΔT= 1/2 Mv² /4.2 ms
.....where M is mass of hammer and m is mass of nail.
2)
power =workdone /time
power = mL/t
where m is mass of ice , l is latent heat. and t is time
thnx
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