please answer the circled question
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Hey
Here is your answer,
1)= 9x^2+6x+1-25y^2
=(3x)^2+2*3x*1+(1)^2-(5y)^2
=(3x+1)^2-(5y)^2
={(3x+1)+5y}{(3x+1)-5y}
=(3x+5y+1)(3x-5y+1)
2)a2 + b2 + 2ab + 2bc + 2ca = (a2 + b2 + 2ab) + (2bc + 2ca)
= (a + b)2 + 2c ( b + a)
= (a + b) (a + b + 2c)
So, factors of (a2 + b2 + 2ab + 2bc + 2ca) are (a + b) (a + b + 2c).
3)estimating the value be 3
x = 3
x3 - 3x2 + 2x -6=0
(3*3*3) -3*3*3 +2*3 -6=0
27 - 27 +6 _6=0
hence the value of x is 3
Hope it helps you!
Here is your answer,
1)= 9x^2+6x+1-25y^2
=(3x)^2+2*3x*1+(1)^2-(5y)^2
=(3x+1)^2-(5y)^2
={(3x+1)+5y}{(3x+1)-5y}
=(3x+5y+1)(3x-5y+1)
2)a2 + b2 + 2ab + 2bc + 2ca = (a2 + b2 + 2ab) + (2bc + 2ca)
= (a + b)2 + 2c ( b + a)
= (a + b) (a + b + 2c)
So, factors of (a2 + b2 + 2ab + 2bc + 2ca) are (a + b) (a + b + 2c).
3)estimating the value be 3
x = 3
x3 - 3x2 + 2x -6=0
(3*3*3) -3*3*3 +2*3 -6=0
27 - 27 +6 _6=0
hence the value of x is 3
Hope it helps you!
varshneysamyakoxg8tj:
Thanks
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