Physics, asked by soniakamboj006pab3w5, 1 year ago

please answer the circled questions...

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Answered by guuda

here is the answer for 10th question

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guuda: best of luck for exam....

guuda: current through 3R resistance is i(1) = R(2) .I square /R(1) +R(2) = 6R . I square / 6R + 3R = 2R . I square

guuda: 6R . I / 9R = 2 I / 3...... also current through 6R resistance is similarly i (2) = I / 3....... current through R resistance is I ........ p (1) =i(1) square ×3R = 4 I square / 9 ×3R = 4 I square R / 3 ......... P(2)= i (2) square × 6R = I square × 6R / 9 = 2 I square R / 3 .........P (3)= I square ×R ...... therefore P (1) : P(2) :P(3) =4 I square R /3 : 2 I square R /3 : I square R :==== 4:2:3.....

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