Question

Please answer the correct answers

Answer 1

Answer:

1. x²-2x-8=0

x²-4x+2x-8=0

x(x-4)+2(×-4)=0

(x-4) (x+2) =0

x-4=0 》x=4 , x+2=0 》 x= -2

Verify

put,x=4 put,x= -2

then, 4²-2×4-8 then, (-2)²-2×(-2)-8

16 -8-8 4+4-8

16-16=0 8-8=0

So, 4and-2 are the zeros of x²-2x-8.