Question

Please answer
The diagnols of a rhombus measure 16 cm and 30 cm. Find its perimeter
Please answer and tell the method too

Answer 1

Hope this will be useful for u

Answer 2

we know that diagonals of a rohmbus bisect each other at right angles so 1/2*16 and 1/2*30
which is 8,15 by Pythagoras theorem it will be according to figure bc2=ob2+oc2
8^2+15^2=bc2
√289=17
perimeter of rhombus is 4*side so 4*17=68