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The diagnols of a rhombus measure 16 cm and 30 cm. Find its perimeter
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bhoomichaudhary:
Thanks a lot....this helped me
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we know that diagonals of a rohmbus bisect each other at right angles so 1/2*16 and 1/2*30
which is 8,15 by Pythagoras theorem it will be according to figure bc2=ob2+oc2
8^2+15^2=bc2
√289=17
perimeter of rhombus is 4*side so 4*17=68
which is 8,15 by Pythagoras theorem it will be according to figure bc2=ob2+oc2
8^2+15^2=bc2
√289=17
perimeter of rhombus is 4*side so 4*17=68
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