Math, asked by nrajeswaran04, 9 months ago

please answer the (e) sum


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Answered by ananthukrishnan456
0

Answer:

3x(x +1 ) -2(y +2)

Step-by-step explanation:

3x^2 - 4y +3x -[(x^2 -(x^2 + y) -2y +4]

= 3x^2 - 4y +3x -[x^2 - x^2 -y +2y + 4]

= 3x^2 -4y +3x - 0 + y - 2y - 4

= 3x^2 - 4y +3x + 2y - 4

= 3x^2 +3x -2y - 4

= 3x(x +1 ) -2(y +2)

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