Math, asked by gvv65, 8 months ago

Please answer the following I will mark it as Brainliest

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Answered by vanshika1122
2

Answer:

which one to answer ....

Answered by biligiri
0

Answer:

to evaluate

[2ⁿ⁺³ - 2(2ⁿ)] / 2⁽²ⁿ⁺²⁾

=> [2ⁿ * 2³ - 2 * 2ⁿ] / [2²ⁿ * 2²]

=> [2ⁿ ( 2³ - 2 )] / (2²ⁿ * 2²)

=> 2ⁿ ( 6) / 2²ⁿ * 4

=> 6 / 2⁽²ⁿ ⁻ ⁿ⁾ * 4

=> 6 / 2ⁿ * 4

=> 3 / 2ⁿ * 2

=> 3 / 2ⁿ⁺¹

option C

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