Question

Please answer the following question ​

Answer 1

Step-by-step explanation:

Ab =  6 (A+b)

Ab = 36 (A² + b² + 2 Ab)

36 A² + 71 A b + 36 b² = 0

Let   A/b =  x

so   36 x² +  71 x + 36 = 0

           x = [ -71 +- √(71² - 4*36²) ]/2

A + b =  1/6 * √Ab   --- (1)

(A - b)² = (A + b)² - 4 a b 

            = Ab/36  - 4 a b

            = - 143 A b/36       --- (2)

A - b   = + √(-143Ab) /6       or    - √(-143 Ab) /6      --- (3)

If  Ab is positive then  (1) is valid, but (3) is not valid.  If  Ab is negative, then (1) is not valid,  but (2) is valid.

There are no real solutions to the given problem. Only complex number solutions exist.

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Answer 2

Step-by-step explanation:Ab =  6 (A+b)

Ab = 36 (A² + b² + 2 Ab)

36 A² + 71 A b + 36 b² = 0

Let   A/b =  x

so   36 x² +  71 x + 36 = 0

           x = [ -71 +- √(71² - 4*36²) ]/2

A + b =  1/6 * √Ab   --- (1)

(A - b)² = (A + b)² - 4 a b 

            = Ab/36  - 4 a b

            = - 143 A b/36       --- (2)

A - b   = + √(-143Ab) /6       or    - √(-143 Ab) /6      --- (3)

If  Ab is positive then  (1) is valid, but (3) is not valid.  If  Ab is negative, then (1) is not valid,  but (2) is valid.

There are no real solutions to the given problem. Only complex number solutions exist.