Question

Please answer the following question.

Answer 1

in ∆ABC. angle B = 90° , BC = 48 cm , AB= 14 cm. by Pythagoras theorem.....

AC = 50 cm......
in quadrilateral OPBQ. ...... Angle P =B=Q=90° O = 90°......Op=OQ=r(radii of same circle )....
OPBQ is a square
BQ=OQ=OP=BP=r

AQ=14-r and CP=48-r......{ AQ=AR,,CP=CR..... because tangents to the circle from external point are equal }
AR=14-r and CR=48-r.......
but AR+CR=AC....
14-r+48-r=50--------62-2r=50.......
2r=62-50=12----------r=12/2=6cm.......

please mark it as brainliest ☺️☺️ please

Answer 2

Hey User!!
Your answer is in the attachment.

Hope it helps!!
@charlie16 ✨