Math, asked by prishabhatia02, 5 hours ago

Please answer the following question and detail and provide explanations for all the steps​

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Answers

Answered by aakilshah
0

Answer:

1 2 ka 4 4 2 ka 1

HAHHAHAHAHA

Answered by WildCat7083
104

First of all, we need to rationalize the denominator.

 \tt\frac{ 1  }{ 5-2 \sqrt{ 6  }    }

 \tt\frac{5+2\sqrt{6}}{\left(5-2\sqrt{6}\right)\left(5+2\sqrt{6}\right)}

 \tt\frac{5+2\sqrt{6}}{5^{2}-\left(-2\sqrt{6}\right)^{2}}

 \tt\frac{5+2\sqrt{6}}{25-\left(-2\sqrt{6}\right)^{2}}

 \tt\frac{5+2\sqrt{6}}{25-4\left(\sqrt{6}\right)^{2}}

 \tt\frac{5+2\sqrt{6}}{25-24}

 \tt\frac{5+2\sqrt{6}}{1}

 \tt  \red{ x = 5+2\sqrt{6} }

nd now you can insert the value of x in the equation and get the answer

\large \bold{@WildCat7083}

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