Question

please answer the following question as soon as possible. spammers will be reported ​

Answer 1

Step-by-step explanation:

AB=AC so ABC =ACB(isosceles traingle prop)

DBC=DCB(")

so

ABC+DBC=ACB+DCB

Draw AD

DB=DC

BA=CA

AD=AD

tria ABD =~  tria ACD

so BAD = CAD (CPCT)

thus it bisects

mark brainliest pls

Answer 2

Answer:

IF WE DRAW A LINE FROM A TO D.

IN TRIANGLE ABD AND ACD

AB=AC

BD=CD

AD=AD COMMON

ACCORDING TO SSS CRITERIA THEY ARE EQUAL.

SO ANGLE ABD= ANGLE ACD

ANGLE A = ANGLE BAD+ ANGLE CAD

ANGLE A = 2 ANGLE BAD ( BOTH ANGLES ARE EQUAL )

ANGLE A÷2 = ANGLE BAD.

SO IT WAS PROVED THAT ANGLE A WAS BISECTED BY AD..

DO SAME AS FOR D..

HENCE PROVED....

HOPE IT HELPS YOU......

THANKYOU......