Math, asked by mohutter678, 4 months ago

Please answer the following questions
1) 9c + 1 = 10

2) 8 = 3a – 4

3) 13 + 7x = 27

4) n – 31 = 2 4

5) 42 + 5t = 8t

6) 6y – 5 = 7

7) m + 9 = 11

8) 17 – q = 6

9) 1 + 2r = 35

10) 4p – 3 = 17

Answers

Answered by deeptiojha5
6

Answer:

A)9c+1=10

9c=10-1

9c=9

c=1

B)8=3a-4

8+4=3a

12=3a

12/3=a

a=4

C)13+7x=27

7x=27-13

7x= 14

x=14/7

x=2

D)n-31=24

n=24+31

n=55

E)42+5t=8t

42=13t

42/13=t

3.23=t

F)6y-5=7

6y=7+5

6y=12

y=2

do the following like this

Answered by omk47128
2

Answer:

1)9c=10-1

9c=9

C=9\9

C=1

2)8+4=3a

12=3a

12/3=a

4=a

3)7x=27-13

7x=14

X=14/7

X=2

4)n=24+31

N=55

5)42=8t-5t

42=3t

42/3=t

0.0715=t

6)6y=7+5

6y=12

Y=12/6

Y=2

7)m=11-9

M=2

8)17-6=q

11=q

9)2r=35-1

2r=34

R=34/2

R=17

10)4p=17+3

4p=20

P=20/4

P=5

Plz mark me as brainlest

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