Question

please answer the following questions:
1)The digit in the ten’s place of a two-digit number is three times that in the one’s place. If the digits are reversed, the new number will be 36 less than the original number. Find the number.
2)I have a total of Rs 400 in Rs2, Rs 5 and Rs 10. Number of Rs 5 coins is 2 times the number of Rs 2 coins. The total number of coins is 76. How many coins of each denomination are with me?

Answer 1

Answer:

1) 62 2) 2 Rs x 20, 5 Rs x 40, 10 Rs x 16

Step-by-step explanation:

1) ab two digit number, ab=10a+b

a=3b

ab-ba=36 => 10a+b-10b-a=36 =>a-b=4

a-b=3b-b=4=> 2b=4 => b=2 and a=6

Number is 62

proof: 62-26=36

2) 2Rs.- x, 5Rs.- y, 10 Rs.- z

y=2x

a) x+y+z=76 =>x+2x+z=76 => 3x+z=76 =>6x+2z=152

b) 2x+5y+10z=400 => 2x+5*2x+10z=400=> 12x+10z=400 => 6x+5z=200

From the difference in a) and b) we get: 3z=48=> z=16

6x+5*16=200 =>x=20

y=2x=40

So number of 2 Rs. = 20, 5 Rs. = 40, 10 Rs. = 16

Proof:

20+40+16=76

20*2+40*5+16*10=200

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