Math, asked by harshad6022, 5 months ago

please answer the following questions​

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Answered by saiyedfazil
4

2x^2+kx-5=50

2×5^2+k×5-5=50

2×25+5k=50+5

50+5k=55

5k=5

k=5/5=1

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Answered by Netra1707
1

Answer:

p(x) = 2x^2 + kx - 5

50 = 2(5)^2 + k(5) - 5

50 = 2(25) + 5k - 5

50 = 50 + 5k - 5

50 - 50 = 5k - 5

0 = 5k - 5

0 + 5 = 5k

5 = 5k

5/5 = k

1 = k

Therefore, k=1

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