please answer the following questions
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2x^2+kx-5=50
2×5^2+k×5-5=50
2×25+5k=50+5
50+5k=55
5k=5
k=5/5=1
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Answer:
p(x) = 2x^2 + kx - 5
50 = 2(5)^2 + k(5) - 5
50 = 2(25) + 5k - 5
50 = 50 + 5k - 5
50 - 50 = 5k - 5
0 = 5k - 5
0 + 5 = 5k
5 = 5k
5/5 = k
1 = k
Therefore, k=1
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