please answer the following questions
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So basically i would suggest you remember this result as it is very useful
Ley each side be a
So QS=QR (in equilateral triangle median and altitudes are same)
So PS^2 = a^2 - (a^2/4) = 3a^2/4
So PS = rt3a^2/2
So, just put the value of PS to find side and then put the value of side in area
So, a= rt6 cm (=PQ)
Now area of PQR= rt3/4 x a^2 = 1.5rt3 cm square
Ley each side be a
So QS=QR (in equilateral triangle median and altitudes are same)
So PS^2 = a^2 - (a^2/4) = 3a^2/4
So PS = rt3a^2/2
So, just put the value of PS to find side and then put the value of side in area
So, a= rt6 cm (=PQ)
Now area of PQR= rt3/4 x a^2 = 1.5rt3 cm square
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