Question

Please answer the given attachment and no irrelevant answers
Note : irrelevant answers will be deleted​​

Answer 1

Let, f (x) = 2x4-7x3-13x2+63x-45

The factors of the constant term – 45 are

--+1,--+3,--+5,--+9,-- +15 and --+45

f(1) = 2 (1)4 – 7 (1)3 – 13 (1)2 + 63 (1) – 45

= 2 – 7 – 13 + 63 – 45

= 0

And,

f (3) = 2 (3)4 – 7 (3)3 – 13 (3)2 + 63 (3) – 45

= 162 – 189 – 117 + 189 – 45

= 0

So, (x – 1) and (x + 3) are the factors of f (x)

(x – 1) (x + 3) is also a factor of f (x)

Let us now divide

f (x) = 2x4-7x3-13x2+63x-45 by (x2 – 4x + 3) to get the other factors of f (x)

Using long division method, we get

2x4-7x3-13x2+63x-45 = (x2 – 4x + 3) (2x2 + x – 15)

2x4-7x3-13x2+63x-45 = (x – 1) (x – 3) (2x2 + x – 15)

Now,

2x2 + x – 15 = 2x2 + 6x – 5x – 15

= 2x (x + 3) – 5 (x + 3)

= (2x – 5) (x + 3)

Hence, 2x4-7x3-13x2+63x-45 = (x – 1) (x – 3) (x + 3) (2x – 5)

PLEASE MARK BRAINLIEST!!!