please answer the ii question
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A= 2y²+3x-x²
B=3x²-y²
(ii) A-B = (2y²+3x-x²)-(3x²-y²)
= 2y²+3x-x²-3x²+y²
= 3y²-4x²+3x
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B=3x²-y²
(ii) A-B = (2y²+3x-x²)-(3x²-y²)
= 2y²+3x-x²-3x²+y²
= 3y²-4x²+3x
please follow me
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