please answer the maths question and correct or do not answer
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in ∆ABC and ∆QBP
AB=BQ(given in question)
angle ABC= angle QBP (vertically opposite angles)
BC=BP (given in question)
therefore by SAS congruency
∆ABC is congruent to ∆QBP
By corresponding parts of congruent triangle that is CPCT
AC=PQ
angle BAC= angle BQP
angle ACB= angle QPB
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