Please answer the physics question fast
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Work done by the block = kinetic energy of the bullet
= 1/2 mv²
we know that, work = force x displacement.
F x d = 1/2 mv²
m x a x d = 1/2mv²
a x d = v²/2
a = v²/2d
a = 1600/ 2 x 4 x 10⁻²
a = 200/10⁻²
a = 2 x 10⁴ m/s²
now, using kinematic equation,
v = u + at
0 = u -at
u = at
t = u/a
= 40/2 x 10⁴
t = 2 x 10⁻³ s
This is the required answer.
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