Question

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Answer 1

Question:

The width of a rectangle is three-fourth of its length. Find the dimensions of a rectangle if it's perimeter is 28m

Answer:

• Length = 8cm
• Width = 6cm

Explanation:

Let's say the length of the rectangle is x

Then the width will be ¾ of x

= $\rm\dfrac{3x}{4}$

We know that,

Perimeter of a rectangle = $2(l + b)$

Where, $l$ denotes the length and $b$ is the width.

According to the question,

$\rm \implies \: 2 \bigg(x + \dfrac{3x}{4} \bigg) = 28$

$\rm \implies \: 2 \bigg( \dfrac{4x + 3x}{4} \bigg) = 28$

$\rm \implies \: 2 \bigg( \dfrac{7x}{4} \bigg) = 28$

$\rm \implies \: \dfrac{14x}{4} = 28$

$\rm \implies \:x = \dfrac{28 \times 4}{14}$

$\rm \therefore \: x = 8$

Hence,

Length of the rectangle is 8m

And also, the breadth ¾ of 8 = 6m

Answer 2

ANSWER:-

let, breadth to be x According to question

length=3/4x

perimeter=28cm

2(1+b)=28cm

2(x+3x/4)=28cm

x+3x/4=28/2=14cm

4x+3x/4=14cm 7x/4=14cm

7x=14x4cm

7x=56cm

x=56/7cm

x=8cm

length=3/4x

=3/4x8

=6cm

width =X

=8cm

I Hope It's Helpful My Friend.