Question

please answer the qn​

Answer 1

Answer:

let a be any positive integer abd b=6 Then,by Euclid's division lemma , a= 6q+r for some integer q>=0 and r=0,1,2,3,4or 5 because 0>=r <6.

so a=6q or a=6q+1or a=6q+2=2 (3q+1)or a=6q+3 or a=6q+4=2 (3q+1) or a=6q+5.

since a is an odd integer,a connot be 6q or 6q+2 or 6q+4 as they are all divisible by 2.

therefore,any positive odd integer is of the form 6q+1 or 6q+3or 6q+5.