Question

please answer the quention with details​

Answer 1

Step-by-step explanation:

${x}^{2 } + 1 = \sqrt{3} x$

dividing both sides by x, we get

$x + \frac{1}{x } = \sqrt{3}$

we have,

${a}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} )$

$= (a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab)$

$= (a + b)( (a + b) ^{2} - 3ab)$

putting,. a=x and b=1/x

$= \sqrt{3} ( { \sqrt{3} }^{2} - 3)$

$= \sqrt{3} \times 0$

$= 0$