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the numbers which are divisible by 2 or 5 and from 1 to 100 are
2,4,5,6,8,10,12,14,15,16,18,20,...98,100
sum of them = k
(2+4+6+8+----98+100) +(5+15+25+...95) =k
[50*102]/2 + [10*100]/2=k
[100*51/2]+[10*100]/2 =k
[(51+10)100/2] =k
6100/2 =k---(1)
divide (1) with 610
6100/(610*2) = k/610
10/2= k/610
5 = k/610
∴k/610 = 5
2,4,5,6,8,10,12,14,15,16,18,20,...98,100
sum of them = k
(2+4+6+8+----98+100) +(5+15+25+...95) =k
[50*102]/2 + [10*100]/2=k
[100*51/2]+[10*100]/2 =k
[(51+10)100/2] =k
6100/2 =k---(1)
divide (1) with 610
6100/(610*2) = k/610
10/2= k/610
5 = k/610
∴k/610 = 5
john44:
but answer should be integer type
i will check again
john is it correct
no
i need to check the answer
i think it is correct
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Answer:
the numbers which are divisible by 2 or 5 and from 1 to 100 are
2,4,5,6,8,10,12,14,15,16,18,20,..98,100
sum of them = k
(2+4+6+8+----98+100) +(5+15+25+...95) =k
[50*102]/2 + [10*100]/2=k [100*51/2]+[10*100)/2 =k
[(51+10)100/2] =k 6100/2 =k--(1)
divide (1) with 610
6100/(610*2) = k/610
10/2= k/610
5 = k/610
...k/610 = 5
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