Question

please answer the question​

Answer 1

Answer:

mass of bullet= 50 g which is 0.05kg

speed of bullet=200 metre per second

initial kinetic energy of bullet=1/2mv^2

initial kinetic energy=0.5*0.05*200*200= 1000JOULES

So THE KINETIC ENERGY OF EMERGENT BULLET IS 100

let the speed v

bye formula of kinetic energy= k.e=1/2mv^2

100=1/2*0.05*v^2

v^2=200/0.05=20000/5

v^2=4000

v=63.24m/s