Question

please answer the question​

Answer 1

Step-by-step explanation:

angle DAY = angle CBX [given]

DA=CB [given]

Now, AX=BX

AX+XY=BY+XY

AY=ND

triangle DAY congruent triangle CBX

[By SAS congruence ]

Answer 2

in ∆ DAY and ∆CBX

DA=CB (given)

<DAY=<CBX (90°)

AX =BY ( given)

XY+AX=XY+BY (adding XY on both

sides, since AX=BY

and XY is common

both triangles)

therefore, AY=BX

therefore, ∆DAY congruent to ∆CBX

THANK YOU...