CBSE BOARD X, asked by sgt2004, 1 year ago

please answer the question

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Answered by Anonymous
16

\huge{\mathfrak{\red{\underline{Answer :-}}}}

Given :-

First term(a) = 1

\sf{a_{n} = 20}

\sf{S_{n} = 399}

To Find :-

Value of n.

Solution :-

We know that,

\huge{\boxed{\red{\bf{\underline{S_{n} = \frac{n}{2}(a +l)}}}}}

_______________[Put Values]

399 = n (20 + 1)/2

399 = 21n/ 2

399 * 2 = 21n

798 = 21n

798/21 = n

38 = n

\huge{\boxed{\red{\bf{\underline{n = 38}}}}}

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