please answer the question
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Step-by-step explanation:
A) BQA=BPA(given)
QAB= PAB(line l is the angular bisector of angle A)
ABP=BPQ(by angle sum property)
AB=AB(common)
BY ASA PROPERTY,
BOTH THE TRIANGLES ARE CONGRUENT...
B) AS THE TRIANGLES ABQ AND ABP ARE CONGRUENT,THE CORRESPONDING PARTS ARE EQUAL...
SO,BP=BQ...
HOPE IT HELPS...
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