Math, asked by singbijender9, 9 months ago

please answer the question​

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Answered by kaviyakrishna06
0

Step-by-step explanation:

use the formula to get the answer

Answered by Anonymous
8

\sf Water\: flowing \:in\: the \:river \:in \:1 \:hour\: \\ = \:2km\:=\:2000m

\scriptsize\:\: {(∵ \:1 km \:= \:1000 m)}

\sf Water \:flowing \:in \:the \:river \:in \:60 \:min \:= \:2000 \:m

\scriptsize\:\: {(∵ 1 \:hour\: =\: 60 min)}

\sf Water \:flowing\: in \:the\: river\: in\: 1\: min\: \\= \:\dfrac{2000 m}{60}\:= \:\dfrac{100 m}{3}

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\sf ∵ The\: shape \:of \:the\: river\: is\: of \:the\: form\: cuboid

\sf Its \:dimensions\: will \:be\: :

\sf  Length\: =\: \dfrac{100 m}{3} m

\sf Breadth \:= \:40 m

\sf  Height  \:= \:3 m

\sf ∴ Volume\: of \:water\: falling \: into \:the\: sea\:  in \:a \:minute\: \\ \implies length \times breadth \times  height

\implies ( \dfrac{100}{3}  \times 40 \times 3) {m}^{3}

\implies (100 \times 40) {m}^{3}

\implies 4000  \: {m}^{3}

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