Question

please answer the question​

Answer 1

Answer:

$\: 16 {a}^{2}$

Step-by-step explanation:

>> (2a + 3b)² + 2(2a+3b)(2a-3b) + (2a-3b)²

Using the formula: (a+b)² = a² + 2ab + b²

So here ,

a = (2a + 3b)

b = (2a - 3b)

>> [(2a + 3b) + (2a - 3b)]²

>> (2a + 3b + 2a - 3b)²

>> (2a + 2a)²

>> (4a)²

$= \: 16 {a}^{2}$

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Answer 2

Answer:

16a^2

Step-by-step explanation:

The given question is of the form

a^2+2ab+b^2=(a+b)^2

(2a+3b)^2+2(2a+3b)(2a-3b)+(2a-3b)^2

Using the above formula we can write the question as

(2a+3b+2a-3b)^2=(4a)^2=>16a^2

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