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Answer:
In △ABC, ∠ABC + ∠ACB + ∠BAC = 180° 69° + 31° + ∠BAC = 180° ⇒ ∠BAC = 180° – 100° = 80° ∠BDC = ∠BAC (Angles in the same segment) ∴ ∠BDC = 80°
Answer:
In △ABC, ∠ABC + ∠ACB + ∠BAC = 180° 69° + 31° + ∠BAC = 180° ⇒ ∠BAC = 180° – 100° = 80° ∠BDC = ∠BAC (Angles in the same segment) ∴ ∠BDC = 80°