please answer the question
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Answered by
1
Answer:
1/logxy base x + 1/logxy base y
=> 1/(logxy/logx) + 1/(logxy/logy)
=> logx/logxy + logy/logxy
=> (logx+logy)/logxy
=> logxy/logxy
=> 1
Answered by
0
Answer:
I am sorry I don't know the answer
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