Chemistry, asked by Anonymous, 10 months ago

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Answered by aryans01

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P is Ethanol (C2H5OH)

When Sodium is added to the Test Tube Containing P then Sodium Ethoxide (C2H5ONa) and Hydrogen gas (H2)

Therefore P=Ethanol - CH3COOH

Q=Sodium Ethoxide - C2H5ONa

Gas =Hydrogen Gas - H2

Required Reaction is :-

Na +C2H5OH ---> C2H5ONa +H2

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