Math, asked by manjunathamv1970, 7 months ago

please answer the question

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Answers

Answered by omm7554
1

Step-by-step explanation:

X-1/x-2+ x-3/x-4=10/3

=>(x-1)(x-4)+(x-3)(x-2)/(x-2)(x-4)=10/3

=>x^2-4x-x+4+x^2-2x-3x+6/x^2-4x-2x+8=10/3

=>2x^2-5x+4-5x+6/x^2-6x+8=10/3

=>2x^2-10x+10/x^2-6x+8=10/3

=>3(2x^2-10x+10)=10(x^2-6x+8)

=>6x^2-30x+30=10x^2-60x+80

=>10x^2-6x^2-60x+30x+80-30=0

=>4x^2-30x+50=0

=>2(2x^2-15x+25)=0

=>2x^2-15x+25=0

=>2x^2-10x-5x+25=0

=>2x(x-5)-5(x-5)=0

=>(x-5)(2x-5)=0

=>x-5=0 and 2x-5=0

=>x=5 and x=5/2.

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