Math, asked by student015, 1 year ago

please answer the question

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Answered by nova31

In triangle OAP and triangle OBQ
PA=QB(given)
angleOAB=angleOBQ (each90)
angle AOP=angleQOB(veryically opposite)
therefore triangle OAP=triangleOBQ(AAS)
OA=QB(cpct)
proved

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