Math, asked by brainly73, 1 year ago

. Please answer the question

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Answers

Answered by siddhartharao77
1
Given inner diameter d = 3 3/4

                                        = 15/4.


Then the radius r = 1/2 * diameter

                              = 1/2 * 15/4

                              = 15/8cm.


Given thickness = 5/7cm.


Therefore the outer radius of the pipe = 15/8 + 5/7

                                                                 = 145/56.

                                                                 = 2  \frac{33}{56}  cm



Hope this helps!
Answered by MOSFET01
1

 =  \frac{15}{8}  +  \frac{5}{7}  \\  =  \frac{105 + 40}{56}  \\  =  \frac{145}{56}  = 2.58cm

brainly73: sir the answer is in mixed fraction
brainly73: the 1 one is right
brainly73: no it is also correct
MOSFET01: Ha ji to 2.33/56 =145/56 he hota hei
brainly73: ha mene nahi deka
brainly73: ops
MOSFET01: :-)
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