Question

please answer the question

Answer 1

$sinA = \frac{opposite}{hypotenuse} = \frac{4}{5} \\ cosA = \frac{adjacent}{hypotenuse} = \frac{3}{5} \\ tanA = \frac{opposite}{adjacent} = \frac{4}{3} \\ cosecA = \frac{hypotenuse}{opposite} = \frac{5}{4} \\ secA = \frac{hypotenuse}{adjacent} = \frac{5}{3} \\ cotA = \frac{adjacent}{opposite} = \frac{3}{4}$

Answer 2

Answer:

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