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Step-by-step explanation:
area of the given figure is 66cm
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Answer:
AGFH is a square
area of square = a2 = 4sq = 16cm2
FEDI isca square
area of square = a2 = 4sq = 16cm2
AH = GF = 4cm
AB = AH + HB
12 = 4 + HB
12 - 4 = HB
HB = 8cm
HBCF is a rectangle
area of rectangle = l * b = 8 * 3 = 24cm2
ICD is a triangle
IC = JB
HJ = ED = 4cm
HB = HJ + JB
8 = 4 + JB
8 - 4 = JB
JB = 4cm
area of triangle = 1/2 * b * h
1/2 * 4 * 4 = 8cm2
ar[ AGFH] + ar[FEDI] + ar[HBCF] + ar[ICD]
= 16 + 16 + 24 +8
= 64cm2
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