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Answer 1

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Answer 2

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\frac { 1 - 25 } { 3 } - \frac { 3 } { 2 } [ 2 - \frac { x - 5 } { 2 } ] + \frac { x + 3 } { 4 } = 1

12\left(\frac{1-25}{3}-\frac{3}{2}\left(2-\frac{x-5}{2}\right)\right)+3\left(x+3\right)=12

12\left(\frac{-24}{3}-\frac{3}{2}\left(2-\frac{x-5}{2}\right)\right)+3\left(x+3\right)=12

12\left(-8-\frac{3}{2}\left(2-\frac{x-5}{2}\right)\right)+3x+9=12

12\left(-8-\frac{3}{2}\left(2-\left(\frac{1}{2}x-\frac{5}{2}\right)\right)\right)+3x+9=12

12\left(-8-\frac{3}{2}\left(2-\frac{1}{2}x+\frac{5}{2}\right)\right)+3x+9=12

12\left(-8-\frac{3}{2}\left(\frac{4}{2}-\frac{1}{2}x+\frac{5}{2}\right)\right)+3x+9=12

12\left(-8-\frac{3}{2}\left(\frac{9}{2}-\frac{1}{2}x\right)\right)+3x+9=12

12\left(-8-\frac{3}{2}\times \left(\frac{9}{2}\right)-\frac{3}{2}\left(-\frac{1}{2}\right)x\right)+3x+9=12

12\left(-8+\frac{-3\times 9}{2\times 2}-\frac{3}{2}\left(-\frac{1}{2}\right)x\right)+3x+9=12

12\left(-8+\frac{-27}{4}-\frac{3}{2}\left(-\frac{1}{2}\right)x\right)+3x+9=12

12\left(-8-\frac{27}{4}-\frac{3}{2}\left(-\frac{1}{2}\right)x\right)+3x+9=12

12\left(-8-\frac{27}{4}+\frac{-3\left(-1\right)}{2\times 2}x\right)+3x+9=12

12\left(-8-\frac{27}{4}+\frac{3}{4}x\right)+3x+9=12

12\left(-\frac{32}{4}-\frac{27}{4}+\frac{3}{4}x\right)+3x+9=12

12\left(\frac{-32-27}{4}+\frac{3}{4}x\right)+3x+9=12

12\left(-\frac{59}{4}+\frac{3}{4}x\right)+3x+9=12

12\left(-\frac{59}{4}\right)+12\times \left(\frac{3}{4}\right)x+3x+9=12

\frac{12\left(-59\right)}{4}+12\times \left(\frac{3}{4}\right)x+3x+9=12

\frac{-708}{4}+12\times \left(\frac{3}{4}\right)x+3x+9=12

-177+12\times \left(\frac{3}{4}\right)x+3x+9=12

-177+\frac{12\times 3}{4}x+3x+9=12

-177+\frac{36}{4}x+3x+9=12

-177+9x+3x+9=12

-177+12x+9=12

-168+12x=12

12x=12+168

12x=180

x=\frac{180}{12}

x=15