please answer the question....
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by putting value of roots in equation,if it satisfies then you will get your answer
Sumansubhankar:
I knew that...but the answer doesn't satisfy the options
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Hey there !!
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Since, two roots of a quadratic equation are 5/3 and –3/2.
x = 5/3 or x = –3/2
( 3x – 5 ) = 0 or ( 2x + 3 ) = 0
( 3x – 5 ) ( 2x + 3 ) = 0
3x ( 2x + 3 ) – 5 ( 2x + 3 ) = 0
6x² + 9x – 10x – 15 = 0
6x² – x – 15 = 0
Thus, the equation is 6x² – x – 15 = 0.
(3) 6x²–x–15=0 ⬅ ANSWER
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Since, two roots of a quadratic equation are 5/3 and –3/2.
x = 5/3 or x = –3/2
( 3x – 5 ) = 0 or ( 2x + 3 ) = 0
( 3x – 5 ) ( 2x + 3 ) = 0
3x ( 2x + 3 ) – 5 ( 2x + 3 ) = 0
6x² + 9x – 10x – 15 = 0
6x² – x – 15 = 0
Thus, the equation is 6x² – x – 15 = 0.
(3) 6x²–x–15=0 ⬅ ANSWER
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