Math, asked by sreenathr2006, 2 months ago

please answer the question​

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Answers

Answered by apoorva1851
3

Answer:

(3√5+2)^2 just hope this answer will help you

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Answered by mathdude500
1

  \large{\underline {\blue {\bf {Answer \:  -  \: a}}}}

\rm :\implies\: {(3 \sqrt{5}  + 2)}^{2}

\rm :\implies\: {(3 \sqrt{5} )}^{2}  +  {(2)}^{2}  + 2 \times 3 \sqrt{5}  \times 2

\rm :\implies\:45 + 4 + 12 \sqrt{5}

\rm :\implies\:49 + 12 \sqrt{5}

 \boxed{ \pink{\bf :\implies\:(3 \sqrt{5}  + 2)^{2} \: is \: irrational. }}

{\large {\underline {\blue {\bf {Answer - b}}}}}

\rm :\implies\:(5 \sqrt{2}  + 3)(5 \sqrt{2}  - 3)

\rm :\implies\: {(5 \sqrt{2} )}^{2}  -  {(3)}^{2}

\rm :\implies\:50 - 9

\rm :\implies\:41

 \boxed{ \pink{\bf :\implies\:(5 \sqrt{2}  + 3)(5 \sqrt{2} - 3) \: is \: rational. }}

{\large {\underline {\blue {\bf {Answer \:  -  \: c}}}}}

\rm :\implies\:9 \sqrt{6}  \times 4 \sqrt{6}

\rm :\implies\:36  \times 6

\rm :\implies\:216

 \boxed{ \pink{\bf :\implies\:(9 \sqrt{6}  \times 4 \sqrt{6} )\: is \: rational. }}

{\large {\underline {\blue {\bf {Answer \:  -  \: d}}}}}

\rm :\implies\:3 \sqrt{7}  - 5 \sqrt{7}  + 2 \sqrt{7}

\rm :\implies\: \sqrt{7} (3 - 5 + 2)

\rm :\implies\:0

 \boxed{ \pink{\bf :\implies\:3 \sqrt{7}   - 5 \sqrt{7} + 2 \sqrt{7}  \: is \: rational. }}

So,

 \large \underline{ \boxed{ \pink{\bf :\implies\:Option \:  (a) \: is \: correct  }}}

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