Question

please answer the question...

Answer 1

......................

Answer 2

Given x = (1/x) - 5

Now,

(1)

x - 1/x = -5.


(2)

On squaring both sides, we get

(x - 1/x)^2 = (-5)^2

x^2 + 1/x^2 - 2 * x * 1/x = 25

x^2 + 1/x^2 - 2 = 25

x^2 + 1/x^2 = 27

(x + 1/x)^2 - 2 = 27

$(x + \frac{1}{x} ) = \sqrt{29}$


(iii).

x^2 - 1/x^2 = (x + 1/x)(x - 1/x)

                  $= ( -\sqrt{29} )(-5)$

                 $= 5 \sqrt{29}$


x^2 - 1/x^2 = (x + 1/x)(x - 1/x)

                  = $= ( \sqrt{29} )(-5)$

                  = $= -5 \sqrt{29}$



Hope this helps!