Question

please answer the question!​

Answer 1

Step-by-step explanation:

f(x)=x ²−2x+3 have zeroes α,β

⇒α+β=2

⇒α⋅β=3

Now polynomial having α+2,β+2 as roots is

p(x)=x ²−(α+2+β+2)x+(α+2)(β+2)

=x ²−(α+β+4)x+αβ+2(α+β)+4

=x ²−(2+4)x+3+2(2)+4

⇒x ² −6x+11