Question

please answer the question...​

Answer 1

Answer:

aaabdc

Explanation:

Answer 2

GIVEN :–

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• If tan x + cot x = 2 then the value of tan²x + cot²x is :

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(a) 3

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(b) 1

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(c) 2

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(d) 0

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ANSWER :–

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GIVEN :–

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• tan x + cot x = 2

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TO FIND :–

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• tan² x + cot² x = ?

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SOLUTION :–

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$\bf \implies \tan(x) + \cot(x) = 2$

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• Square on both side –

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$\bf \implies \{ \tan(x) + \cot(x) \}^{2} = {(2)}^{2}$

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• Using identity –

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$\bf \implies \large { \boxed{ \bf {(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab}}$

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• So that –

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$\bf \implies \tan^{2} (x)+ \cot^{2} (x) + 2 \tan(x) . \cot(x) = 4$

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$\bf \implies \tan^{2} (x)+ \cot^{2} (x) + 2 \tan(x) . \left \{ \dfrac{1}{ \tan(x) } \right \} = 4$

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$\bf \implies \tan^{2} (x)+ \cot^{2} (x) + 2= 4$

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$\bf \implies \tan^{2} (x)+ \cot^{2} (x) = 4 - 2$

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$\bf \implies \tan^{2} (x)+ \cot^{2} (x) = 2$

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$\bf \implies \large{ \boxed{ \bf \tan^{2} (x)+ \cot^{2} (x) = 2 }}$

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• Hence , Option (c) is correct.